目录

环形队列(Circular Queue)和应用场景

  • 环形队列的特点是,不需要进行动态的内存释放和分配,使用固定大小的内存空间反复使用。 非常的简单和高效
  • 相信大家对队列都不陌生。队列是一种具有先进先出(FIFO)的抽象数据类型。如下图所示:

/images/20230224/img.png
队列原理示意图

可以使用多种数据结构来实现一个基本的队列:

  • 数组

  • 链表 简单队列的应用场景有限,但是它的一些变种却有着非常广泛的应用。

  • 环形队列

  • 双端队列

  • 优先队列 在这里,我们只介绍环形队列

环形队列

/images/20230224/img_1.png

判断队列是否满

  • front:表示队列的第一个元素的位置,front初始值默认为0

  • rear:表示队列的最后一个元素的后一个位置,rear初始值默认为0,因为需要空出一个空间作为“约定”

  • 当队列满时,条件是(rear + 1) % maxSize == front

  • 当队列为空,条件是rear = front

  • 当这样分析后,队列中有效的数据个数为(rear + maxSize - front) % maxSize

  • 队列满了取出一个,再添加一个时,showqueue方法会越界的,要取模

应用场景

Memory Management: The unused memory locations in the case of ordinary queues can be utilized in circular queues. Traffic system: In computer controlled traffic system, circular queues are used to switch on the traffic lights one by one repeatedly as per the time set. CPU Scheduling: Operating systems often maintain a queue of processes that are ready to execute or that are waiting for a particular event to occur. Lock Free Queue: When high performance is required, we don’t want to use lock. Circular Queue can is the top 1 data structure for lock free queue.

实现方式

环形队列使用数组来实现。

Go

  • circular_queue.go
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package circular_queue

import (
    "errors"
)

type CircularQueue struct {
    n    int64
    head int64
    tail int64
    data []int
}

func (this *CircularQueue) IsEmpty() bool {
    return this.head == this.tail
}

func (this *CircularQueue) IsFull() bool {
    return this.tail-this.head == this.n-1
}

func (this *CircularQueue) Push(value int) error {
    if this.IsFull() {
        return errors.New("The queue is full")
    }
    this.data[this.tail&(this.n-1)] = value
    this.tail += 1
    return nil
}

func (this *CircularQueue) Pop() (value int, err error) {
    if this.IsEmpty() {
        err = errors.New("The queue is empty")
        return
    }
    value = this.data[this.head&(this.n-1)]
    this.head += 1

    return
}

func New(n int64) (*CircularQueue, error) {
    if n&(n-1) != 0 {
        return nil, errors.New("n must be the power of 2")
    }

    return &CircularQueue{
        n:    n,
        head: 0,
        tail: 0,
        data: make([]int, n, n),
    }, nil
}
  • circular_queue_test.go
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package circular_queue

import (
    "testing"
)

func TestQueue(t *testing.T) {
    var n int64 = 7
    queue, err := New(n)
    if err == nil {
        t.Error("There should be an error")
    }

    n = 8
    queue, err = New(n)
    if err != nil {
        t.Error("There should be no error")
    }

    if queue.IsEmpty() == false {
        t.Error("The queue should be empty now")
    }

    if queue.IsFull() {
        t.Error("The queue should not be full now")
    }

    for i := 1; i < 8; i++ {
        queue.Push(i)
    }

    if queue.IsEmpty() {
        t.Error("The queue should not be empty now")
    }
    if queue.IsFull() == false {
        t.Error("The queue shoule be full now")
    }

    for i := 1; i < 8; i++ {
        value, err := queue.Pop()
        if err != nil {
            t.Error("There should be no error")
        }
        if value != i {
            t.Errorf("The value poped should be %d, but now is %d", i, value)
        }
    }

    if queue.IsEmpty() == false {
        t.Error("The queue should be empty now")
    }

    _, err = queue.Pop()
    if err == nil {
        t.Error("There should be an error")
    }
}

时间复杂度

O(1)

原文链接:https://www.jianshu.com/p/8691a82d433a